Virtual member call in a constructor

Question

I'm getting a warning from ReSharper about a call to a virtual member from my objects constructor.

Why would this be something not to do?

Answer 1

When an object written in C# is constructed, what happens is that the initializers run in order from the most derived class to the base class, and then constructors run in order from the base class to the most derived class (see Eric Lippert's blog for details as to why this is).

Also in .NET objects do not change type as they are constructed, but start out as the most derived type, with the method table being for the most derived type. This means that virtual method calls always run on the most derived type.

When you combine these two facts you are left with the problem that if you make a virtual method call in a constructor, and it is not the most derived type in its inheritance hierarchy, that it will be called on a class whose constructor has not been run, and therefore may not be in a suitable state to have that method called.

This problem is, of course, mitigated if you mark your class as sealed to ensure that it is the most derived type in the inheritance hierarchy - in which case it is perfectly safe to call the virtual method.

Answer 2

In order to answer your question, consider this question: what will the below code print out when the Child object is instantiated?

class Parent
{
    public Parent()
    {
        DoSomething();
    }

    protected virtual void DoSomething() 
    {
    }
}

class Child : Parent
{
    private string foo;

    public Child() 
    { 
        foo = "HELLO"; 
    }

    protected override void DoSomething()
    {
        Console.WriteLine(foo.ToLower()); //NullReferenceException!?!
    }
}

The answer is that in fact a NullReferenceException will be thrown, because foo is null. An object's base constructor is called before its own constructor. By having a virtual call in an object's constructor you are introducing the possibility that inheriting objects will execute code before they have been fully initialized.

Answer 3

The rules of C# are very different from that of Java and C++.

When you are in the constructor for some object in C#, that object exists in a fully initialized (just not "constructed") form, as its fully derived type.

namespace Demo
{
    class A 
    {
      public A()
      {
        System.Console.WriteLine("This is a {0},", this.GetType());
      }
    }

    class B : A
    {      
    }

    // . . .

    B b = new B(); // Output: "This is a Demo.B"
}

This means that if you call a virtual function from the constructor of A, it will resolve to any override in B, if one is provided.

Even if you intentionally set up A and B like this, fully understanding the behavior of the system, you could be in for a shock later. Say you called virtual functions in B's constructor, "knowing" they would be handled by B or A as appropriate. Then time passes, and someone else decides they need to define C, and override some of the virtual functions there. All of a sudden B's constructor ends up calling code in C, which could lead to quite surprising behavior.

It is probably a good idea to avoid virtual functions in constructors anyway, since the rules are so different between C#, C++, and Java. Your programmers may not know what to expect!

Answer 4

Reasons of the warning are already described, but how would you fix the warning? You have to seal either class or virtual member.

  class B
  {
    protected virtual void Foo() { }
  }

  class A : B
  {
    public A()
    {
      Foo(); // warning here
    }
  }

You can seal class A:

  sealed class A : B
  {
    public A()
    {
      Foo(); // no warning
    }
  }

Or you can seal method Foo:

  class A : B
  {
    public A()
    {
      Foo(); // no warning
    }

    protected sealed override void Foo()
    {
      base.Foo();
    }
  }

Answer 5

In C#, a base class' constructor runs before the derived class' constructor, so any instance fields that a derived class might use in the possibly-overridden virtual member are not initialized yet.

Do note that this is just a warning to make you pay attention and make sure it's all-right. There are actual use-cases for this scenario, you just have to document the behavior of the virtual member that it can not use any instance fields declared in a derived class below where the constructor calling it is.

Answer 6

There are well-written answers above for why you wouldn't want to do that. Here's a counter-example where perhaps you would want to do that (translated into C# from Practical Object-Oriented Design in Ruby by Sandi Metz, p. 126).

Note that GetDependency() isn't touching any instance variables. It would be static if static methods could be virtual.

(To be fair, there are probably smarter ways of doing this via dependency injection containers or object initializers...)

public class MyClass
{
    private IDependency _myDependency;

    public MyClass(IDependency someValue = null)
    {
        _myDependency = someValue ?? GetDependency();
    }

    // If this were static, it could not be overridden
    // as static methods cannot be virtual in C#.
    protected virtual IDependency GetDependency() 
    {
        return new SomeDependency();
    }
}

public class MySubClass : MyClass
{
    protected override IDependency GetDependency()
    {
        return new SomeOtherDependency();
    }
}

public interface IDependency  { }
public class SomeDependency : IDependency { }
public class SomeOtherDependency : IDependency { }

Answer 7

Yes, it's generally bad to call virtual method in the constructor.

At this point, the objet may not be fully constructed yet, and the invariants expected by methods may not hold yet.

Answer 8

Because until the constructor has completed executing, the object is not fully instantiated. Any members referenced by the virtual function may not be initialised. In C++, when you are in a constructor, this only refers to the static type of the constructor you are in, and not the actual dynamic type of the object that is being created. This means that the virtual function call might not even go where you expect it to.

Answer 9

Your constructor may (later, in an extension of your software) be called from the constructor of a subclass that overrides the virtual method. Now not the subclass's implementation of the function, but the implementation of the base class will be called. So it doesn't really make sense to call a virtual function here.

However, if your design satisfies the Liskov Substitution principle, no harm will be done. Probably that's why it's tolerated - a warning, not an error.

Answer 10

One important aspect of this question which other answers have not yet addressed is that it is safe for a base-class to call virtual members from within its constructor if that is what the derived classes are expecting it to do. In such cases, the designer of the derived class is responsible for ensuring that any methods which are run before construction is complete will behave as sensibly as they can under the circumstances. For example, in C++/CLI, constructors are wrapped in code which will call Dispose on the partially-constructed object if construction fails. Calling Dispose in such cases is often necessary to prevent resource leaks, but Dispose methods must be prepared for the possibility that the object upon which they are run may not have been fully constructed.

Answer 11

One important missing bit is, what is the correct way to resolve this issue?

As Greg explained, the root problem here is that a base class constructor would invoke the virtual member before the derived class has been constructed.

The following code, taken from MSDN's constructor design guidelines, demonstrates this issue.

public class BadBaseClass
{
    protected string state;

    public BadBaseClass()
    {
        this.state = "BadBaseClass";
        this.DisplayState();
    }

    public virtual void DisplayState()
    {
    }
}

public class DerivedFromBad : BadBaseClass
{
    public DerivedFromBad()
    {
        this.state = "DerivedFromBad";
    }

    public override void DisplayState()
    {   
        Console.WriteLine(this.state);
    }
}

When a new instance of DerivedFromBad is created, the base class constructor calls to DisplayState and shows BadBaseClass because the field has not yet been update by the derived constructor.

public class Tester
{
    public static void Main()
    {
        var bad = new DerivedFromBad();
    }
}

An improved implementation removes the virtual method from the base class constructor, and uses an Initialize method. Creating a new instance of DerivedFromBetter displays the expected "DerivedFromBetter"

public class BetterBaseClass
{
    protected string state;

    public BetterBaseClass()
    {
        this.state = "BetterBaseClass";
        this.Initialize();
    }

    public void Initialize()
    {
        this.DisplayState();
    }

    public virtual void DisplayState()
    {
    }
}

public class DerivedFromBetter : BetterBaseClass
{
    public DerivedFromBetter()
    {
        this.state = "DerivedFromBetter";
    }

    public override void DisplayState()
    {
        Console.WriteLine(this.state);
    }
}

Answer 12

The warning is a reminder that virtual members are likely to be overridden on derived class. In that case whatever the parent class did to a virtual member will be undone or changed by overriding child class. Look at the small example blow for clarity

The parent class below attempts to set value to a virtual member on its constructor. And this will trigger Re-sharper warning, let see on code:

public class Parent
{
    public virtual object Obj{get;set;}
    public Parent()
    {
        // Re-sharper warning: this is open to change from 
        // inheriting class overriding virtual member
        this.Obj = new Object();
    }
}

The child class here overrides the parent property. If this property was not marked virtual the compiler would warn that the property hides property on the parent class and suggest that you add 'new' keyword if it is intentional.

public class Child: Parent
{
    public Child():base()
    {
        this.Obj = "Something";
    }
    public override object Obj{get;set;}
}

Finally the impact on use, the output of the example below abandons the initial value set by parent class constructor. And this is what Re-sharper attempts to to warn you, values set on the Parent class constructor are open to be overwritten by the child class constructor which is called right after the parent class constructor.

public class Program
{
    public static void Main()
    {
        var child = new Child();
        // anything that is done on parent virtual member is destroyed
        Console.WriteLine(child.Obj);
        // Output: "Something"
    }
} 

Answer 13

Beware of blindly following Resharper's advice and making the class sealed! If it's a model in EF Code First it will remove the virtual keyword and that would disable lazy loading of it's relationships.

    public **virtual** User User{ get; set; }

Answer 14

There's a difference between C++ and C# in this specific case. In C++ the object is not initialized and therefore it is unsafe to call a virutal function inside a constructor. In C# when a class object is created all its members are zero initialized. It is possible to call a virtual function in the constructor but if you'll might access members that are still zero. If you don't need to access members it is quite safe to call a virtual function in C#.

Answer 15

Just to add my thoughts. If you always initialize the private field when define it, this problem should be avoid. At least below code works like a charm:

class Parent
{
    public Parent()
    {
        DoSomething();
    }
    protected virtual void DoSomething()
    {
    }
}

class Child : Parent
{
    private string foo = "HELLO";
    public Child() { /*Originally foo initialized here. Removed.*/ }
    protected override void DoSomething()
    {
        Console.WriteLine(foo.ToLower());
    }
}

Answer 16

I think that ignoring the warning might be legitimate if you want to give the child class the ability to set or override a property that the parent constructor will use right away:

internal class Parent
{
    public Parent()
    {
        Console.WriteLine("Parent ctor");
        Console.WriteLine(Something);
    }

    protected virtual string Something { get; } = "Parent";
}

internal class Child : Parent
{
    public Child()
    {
        Console.WriteLine("Child ctor");
        Console.WriteLine(Something);
    }

    protected override string Something { get; } = "Child";
}

The risk here would be for the child class to set the property from its constructor in which case the change in the value would occur after the base class constructor has been called.

My use case is that I want the child class to provide a specific value or a utility class such as a converter and I don't want to have to call an initialization method on the base.

The output of the above when instantiating the child class is:

Parent ctor
Child
Child ctor
Child

Answer 17

I would just add an Initialize() method to the base class and then call that from derived constructors. That method will call any virtual/abstract methods/properties AFTER all of the constructors have been executed :)

Answer 18

Another interesting thing I found is that the ReSharper error can be 'satisfied' by doing something like below which is dumb to me. However, as mentioned by many earlier, it still is not a good idea to call virtual properties/methods in constructor.

public class ConfigManager
{
   public virtual int MyPropOne { get; private set; }
   public virtual string MyPropTwo { get; private set; }

   public ConfigManager()
   {
    Setup();
   }

   private void Setup()
   {
    MyPropOne = 1;
    MyPropTwo = "test";
   }
}